This is a game where you must count to number from 0 to 1000. However, if the number has a 6 in it, or is divisible by 6, you don't say the number. Instead, you say "Shaggy".

Rules:

  • You can't hard-code the numbers.
  • The number only has to satisfy at least 1 of the following requirements
    • Divisible by 6
    • Number contains a 6
  • Some type of separator is mandatory (12345Shaggy7.. doesn't count)
  • You must count exactly to 1000 from 1.
  • The numbers must be output, but it doesn't matter how (e.g., stdout, writing to a text file, etc.).

Solutions

Jump to C, Swift, JavaScript, PHP Solution.
You can submit your own solution in comment section in same/different programming language. If your solution is better or in different language we'll add here.

C

#include <stdio.h>

int main()
{
    for(int i=1;i<=1000;++i)
    {
        if(i%6)
        {
            for(int m=i;(m>0);m/=10) if (m%10==6) goto l;
            printf("%d,",i);
            continue;
        }
        printf("Shaggy,");
    }
    return 0;
}

Swift

import Foundation

for i in 1...1000 {
    print(i%6<1 || (String(i).range(of: "6") != nil) ? "Shaggy" : "\(i)")
}

JavaScript

<html>
<body>
    <p id="print"></p>
    <script>
        for(i=0;i++<1000;)
        document.getElementById('print').innerHTML += i%6<1|/6/.test(i)?'Shaggy\n':i+'\n';
    </script>
</body>
</html>

PHP

<?
for(;1000>$i++;)
    echo$i%6*!strpbrk($i,6)?$i:Shaggy,"\n";