Define value of x in such a way that the expression (x == x+2) would evaluate to true. No rule for this programming puzzle.

# Solutions

Jump to C, CSharp, JavaScript, PHP Solution.
You can submit your own solution in comment section in same/different programming language. If your solution is better or in different language we'll add here.

## C

``````#include<stdio.h>

int main()
{
double x = 1.0/0.0;
printf("%d",x==x+2);
return 0;
}
``````
``````#include<stdio.h>
#define x 2|0

int main()
{
printf("%d",x==x+2); //Basically, the expression is expanded to (2|0 == 2|(0+2)).
return 0;
}
``````
``````#include<stdio.h>

int main()
{
float x = 1e10;
printf("%d\n", x == x + 2);
}
``````

## CSharp

``````using System;

namespace testcs
{
class Program
{
static int y;
static int x
{
get
{
return y -= 2;
}
}
static void Main(string[] args)
{
Console.WriteLine(x == x + 2);
}
}
}
``````

## JavaScript

``````<html>
<body>
<script>
x = {
value: 0,
valueOf: function () {
this.value += 2;
return this.value;
}
};

alert(x == x + 2);
</script>
</body>
</html>
``````

## PHP

``````<?php
\$x = 1e17;
echo \$x==\$x+2;
``````

## Discussion

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